100 balls,each of mass m,moving with speed v, | vedclass

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(B) The initial momentum of $100$ balls is $P_i = 100mv$ (taking the direction towards the wall as positive).After reflection,the final momentum of th

Vedclass · Accepted Answer

$\frac{200\, mv }{ t }$

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(B) The initial momentum of $100$ balls is $P_i = 100mv$ (taking the direction towards the wall as positive).After reflection,the final momentum of the balls is $P_f = -100mv$ (as they move in the opposite direction with the same speed).The change in momentum of the balls is $\Delta P = P_f - P_i = -100mv - 100mv = -200mv$.The force exerted by the wall on the balls is $F_{wall} = \frac{\Delta P}{t} = -\frac{200mv}{t}$.According to Newton's third law,the force exerted by the balls on the wall is equal in magnitude and opposite in direction to the force exerted by the wall on the balls.Therefore,the magnitude of the force exerted by the balls on the wall is $|F| = \frac{200mv}{t}$.

$100$ balls,each of mass $m$,moving with speed $v$,simultaneously strike a wall normally and are reflected back with the same speed in time $t$. The total force exerted by the balls on the wall is

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