$V$ (stopping potential) is plotted against $\frac{1}{\lambda}$,where $\lambda$ is the wavelength of incident radiation,for two metals.

• A
  Metal $1$ may be gold and metal $2$ may be cesium.
• B
  $\theta_1 > \theta_2$,if metal $1$ is gold and metal $2$ is cesium.
• C
  $\theta_1 = \theta_2$,for any two metals.
• D
  $\theta_1 > \theta_2$,if metal $1$ and metal $2$ are gold and copper respectively.