$5 \%$ of the power of a $100 \, W$ bulb is converted to visible radiation. The average intensity of visible radiation at a distance of $10 \, m$ from the bulb is .......... $W/m^2$.

$A$ parallel plate capacitor has a capacitance $C = 200 \ pF$. It is connected to a $230 \ V$ $AC$ supply with an angular frequency $\omega = 300 \ rad/s$. The $rms$ value of the conduction current in the circuit and the displacement current in the capacitor,respectively,are:

The energy that will be ideally radiated by a $100\,kW$ transmitter in $1$ hour is:

For an $EM$ wave,the electric and magnetic fields are $300 \ V m^{-1}$ and $7.9 \ A m^{-1}$ respectively. The maximum rate of energy flow is, (in $W m^{-2}$)

The energies required to set up in a cube of side $10 \ cm$,$(a)$ a uniform electric field of $10^7 \ V \ m^{-1}$ and $(b)$ a uniform magnetic field of $0.25 \ Wb \ m^{-2}$,are respectively about $(\mu_0 = 4\pi \times 10^{-7} \ H \ m^{-1}, \epsilon_0 = 8.9 \times 10^{-12} \ F \ m^{-1})$.

$A$ radar sends an electromagnetic signal with an electric field $E_{0} = 2.25\,V/m$ and a magnetic field $B_{0} = 1.5 \times 10^{-8}\,T$,which strikes a target on the line of sight at a distance of $3\,km$ in a medium. After that,a part of the signal (echo) reflects back towards the radar with the same velocity and along the same path. If the signal was transmitted at time $t_{0}$ from the radar,then after how much time (in $\times 10^{-5}\,s$) will the echo reach the radar?