$12$ positive charges of magnitude $q$ are placed on a circle of radius $R$ in a manner that they are equally spaced. A charge $Q$ is placed at the centre, if one of the charges $q$ is removed, then the force on $Q$ is
zero
$\frac{q Q}{4 \pi \varepsilon_0 R^2}$ away from the position of the removed charge
$\frac{11 q Q}{4 \pi \varepsilon_0 R^2}$ away from the position of the removed charge
$\frac{q Q}{4 \pi \varepsilon_0 R^2}$ towards the position of the removed charge
Two particles $X $ and $Y$, of equal mass and with unequal positive charges, are free to move and are initially far away from each other. With $Y$ at rest, $X$ begins to move towards it with initial velocity $u$. After a long time, finally
Two identical spheres each of radius $R$ are kept at center-to-center spacing $4R$ as shown in the figure. They are charged and the electrostatic force of interaction between them is first calculated assuming them point like charges at their centers and the force is also measured experimentally. The calculated and measured forces are denoted by $F_c$ and $F_m$ respectively.
($F_c$ and $F_m$ denote magnitude of force)
How did Coulomb find the law of value of electric force between two point charges ?
In given diagram. Find distance of neutral point from particle of charge $e$ is......$cm$
A charge $q$ is placed at the centre of the line joining two equal charges $Q$. The system of the three charges will be in equilibrium, if $q$ is equal to