CH_{3}CH_{2}CN xrightarrow[Ether]{CH_{3}MgBr} | vedclass

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(A) $1$. The reaction of $CH_{3}CH_{2}CN$ (propanenitrile) with $CH_{3}MgBr$ (Grignard reagent) followed by acid hydrolysis $(H_{3}O^{+})$ yields a ke

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$CH_{3}CH_{2}CH_{2}CH_{3}$

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(A) $1$. The reaction of $CH_{3}CH_{2}CN$ (propanenitrile) with $CH_{3}MgBr$ (Grignard reagent) followed by acid hydrolysis $(H_{3}O^{+})$ yields a ketone,$B$,which is butan$-2-$one $(CH_{3}CH_{2}COCH_{3})$.$2$. The reaction is: $CH_{3}CH_{2}CN + CH_{3}MgBr$ $\rightarrow CH_{3}CH_{2}C(NMgBr)CH_{3}$ $\xrightarrow{H_{3}O^{+}} CH_{3}CH_{2}COCH_{3}$ $(B)$.$3$. The subsequent step is the Clemmensen reduction,which uses $Zn-Hg/HCl$ to reduce the carbonyl group $(C=O)$ of the ketone to a methylene group $(-CH_{2}-)$.$4$. Therefore,$CH_{3}CH_{2}COCH_{3} \xrightarrow[HCl]{Zn-Hg} CH_{3}CH_{2}CH_{2}CH_{3}$ ($C$,butane).

$CH_{3}CH_{2}CN$ $\xrightarrow[Ether]{CH_{3}MgBr} A$ $\xrightarrow{H_{3}O^{+}} B$ $\xrightarrow[HCl]{Zn-Hg} C$
The correct structure of $C$ is

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$CH_{3}CH_{2}CN$ $\xrightarrow[Ether]{CH_{3}MgBr} A$ $\xrightarrow{H_{3}O^{+}} B$ $\xrightarrow[HCl]{Zn-Hg} C$The correct structure of $C$ is