0.01, M, KMnO_{4} solution was added to 20.0, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The balanced chemical equation for the reaction between $KMnO_{4}$ and Mohr's salt $(FeSO_{4} \cdot (NH_{4})_{2}SO_{4} \cdot 6H_{2}O)$ in acidic m

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(A) The balanced chemical equation for the reaction between $KMnO_{4}$ and Mohr's salt $(FeSO_{4} \cdot (NH_{4})_{2}SO_{4} \cdot 6H_{2}O)$ in acidic medium is:$MnO_{4}^{-} + 5Fe^{2+} + 8H^{+} ightarrow Mn^{2+} + 5Fe^{3+} + 4H_{2}O$Using the equivalence concept:$n_{factor} 	imes M_{1} 	imes V_{1} = n_{factor} 	imes M_{2} 	imes V_{2}$For $KMnO_{4}$,$n_{factor} = 5$ (reduction of $Mn^{+7}$ to $Mn^{+2}$).For Mohr's salt,$n_{factor} = 1$ (oxidation of $Fe^{+2}$ to $Fe^{+3}$).$5 	imes 0.01 	imes V_{1} = 1 	imes 0.05 	imes 20.0$$0.05 	imes V_{1} = 1.0$$V_{1} = \frac{1.0}{0.05} = 20.0\, mL$The volume of $KMnO_{4}$ used is $20.0\, mL$.The volume left in the $50\, mL$ burette is:$V_{left} = 50.0 - 20.0 = 30.0\, mL$.

$0.01\, M\, KMnO_{4}$ solution was added to $20.0\, mL$ of $0.05\, M$ Mohr's salt solution through a burette. The initial reading of $50\, mL$ burette is zero. The volume of $KMnO_{4}$ solution left in the burette after the end point is $.....\, mL$. (nearest integer)

Similar Questions

To a $25 \, mL$ of $H_2O_2$ solution,an excess of acidified solution of $KI$ was mixed. The liberated $I_2$ required $20 \, mL$ of $0.3 \, M$ hypo $(Na_2S_2O_3)$ solution for neutralization. The volume strength of $H_2O_2$ is......$mL$.

Molarity of $0.2 \ N \ H_2SO_4$ is

Which of the following is required to neutralize $1 \ L$ of $1 \ N \ NaOH$?

When $1 \ L$ of $CO_2$ gas is heated with graphite,the volume of the resulting gas mixture at $STP$ is $1.5 \ L$. Calculate the number of moles of $CO$ gas produced at $STP$.

How many moles of methane are required to produce $22 \ g$ of $CO_2 \ (g)$ after combustion (in $mol$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module