AC voltage V(t) = 20 sin omega t of frequency | vedclass

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(D) The capacitance of the parallel plate capacitor is given by $C = \frac{\varepsilon_0 A}{d}$.Substituting the given values: $C = \frac{8.85 	imes

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$27.79$

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(D) The capacitance of the parallel plate capacitor is given by $C = \frac{\varepsilon_0 A}{d}$.Substituting the given values: $C = \frac{8.85 	imes 10^{-12} 	imes 1}{2 	imes 10^{-3}} = 4.425 	imes 10^{-9} \, F$.The angular frequency is $\omega = 2 \pi f = 2 	imes \pi 	imes 50 = 100 \pi \, rad/s$.The amplitude of the current $I_0$ is given by $I_0 = V_0 \omega C$.Substituting the values: $I_0 = 20 	imes (100 \pi) 	imes (4.425 	imes 10^{-9})$.$I_0 = 2000 	imes 3.14159 	imes 4.425 	imes 10^{-9} \approx 27.79 	imes 10^{-6} \, A$.Therefore,the amplitude of the displacement current is $27.79 \, \mu A$.

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