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(A) $1$. The woman's first child is type $O$,which means the child's genotype is $I^{O} I^{O}$. Since the child inherits one $I^{O}$ allele from each

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$I^{A} I^{O};$ Blood type $A$

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(A) $1$. The woman's first child is type $O$,which means the child's genotype is $I^{O} I^{O}$. Since the child inherits one $I^{O}$ allele from each parent,the woman must possess at least one $I^{O}$ allele.$2$. The woman's second child is type $AB$,which means the child's genotype is $I^{A} I^{B}$. This child must inherit one $I^{A}$ allele from one parent and one $I^{B}$ allele from the other.$3$. The second husband is type $B$. If he is homozygous $(I^{B} I^{B})$,he contributes $I^{B}$ to the child. If he is heterozygous $(I^{B} I^{O})$,he could contribute either $I^{B}$ or $I^{O}$.$4$. Since the child is $I^{A} I^{B}$,the $I^{A}$ allele must have come from the mother. $5$. Combining these facts: The mother must have an $I^{O}$ allele (from the first child) and an $I^{A}$ allele (from the second child). Therefore,her genotype is $I^{A} I^{O}$,which corresponds to blood type $A$.

$A$ woman is married for the second time. Her first husband was $ABO$ blood type $A,$ and her child by that marriage was type $O.$ Her new husband is type $B$ and their child is type $AB.$ What is the woman's $ABO$ genotype and blood type?

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