Choose the complexes which are paramagnetic f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To determine paramagnetism,we check for unpaired electrons in the central metal ion:$(i)$ $K_4[Fe(CN)_6]$: $Fe^{2+}$ is $d^6$. $CN^-$ is a strong

Vedclass · Accepted Answer

$(ii)$ and $(iii)$

Vedclass · Answer

(C) To determine paramagnetism,we check for unpaired electrons in the central metal ion:$(i)$ $K_4[Fe(CN)_6]$: $Fe^{2+}$ is $d^6$. $CN^-$ is a strong field ligand,causing pairing. Configuration: $t_{2g}^6 e_g^0$. No unpaired electrons (diamagnetic).(ii) $K_3[Cr(CN)_6]$: $Cr^{3+}$ is $d^3$. Configuration: $t_{2g}^3 e_g^0$. Three unpaired electrons (paramagnetic).(iii) $K_3[Fe(CN)_6]$: $Fe^{3+}$ is $d^5$. $CN^-$ is a strong field ligand,causing pairing. Configuration: $t_{2g}^5 e_g^0$. One unpaired electron (paramagnetic).(iv) $K_2[Ni(CN)_4]$: $Ni^{2+}$ is $d^8$. $CN^-$ is a strong field ligand,causing pairing in square planar geometry. Configuration: $d_{xy}^2 d_{yz}^2 d_{xz}^2 d_{z^2}^2 d_{x^2-y^2}^0$. No unpaired electrons (diamagnetic).Thus,$(ii)$ and $(iii)$ are paramagnetic.

List-$I$ (Coordination compounds)	List-$II$ (Number of unpaired electrons)
$A$. $[Cr(CN)_6]^{3-}$	$I$. $0$
$B$. $[Fe(H_2O)_6]^{2+}$	$II$. $3$
$C$. $[Co(NH_3)_6]^{3+}$	$III$. $2$
$D$. $[Ni(NH_3)_6]^{2+}$	$IV$. $4$

Choose the complexes which are paramagnetic from the following:
$(i)$ $K_4[Fe(CN)_6]$
(ii) $K_3[Cr(CN)_6]$
(iii) $K_3[Fe(CN)_6]$
(iv) $K_2[Ni(CN)_4]$

Similar Questions

The $d-$electron configurations of $Cr^{2+}, Mn^{2+}, Fe^{2+}$ and $Co^{2+}$ are $d^4, d^5, d^6$ and $d^7$ respectively. Which one of the following will exhibit minimum paramagnetic behaviour?
(At. nos. $Cr = 24, Mn = 25, Fe = 26, Co = 27$)

Which of the following does not show optical isomerism?

The metal ions that have the calculated spin-only magnetic moment value of $4.9 \ B.M.$ are:
$A. Cr^{2+}$ $B. Fe^{2+}$ $C. Fe^{3+}$ $D. Co^{2+}$ $E. Mn^{3+}$
Choose the correct answer from the options given below:

The spin-only magnetic moment value of the square planar complex $[Pt(NH_3)_2 Cl(NH_2 CH_3)] Cl$ is $B.M.$ (Nearest integer). (Given atomic number for $Pt = 78$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Choose the complexes which are paramagnetic from the following:$(i)$ $K_4[Fe(CN)_6]$(ii) $K_3[Cr(CN)_6]$(iii) $K_3[Fe(CN)_6]$(iv) $K_2[Ni(CN)_4]$