A (C_{4}H_{8}Cl_{2}) xrightarrow{text{Hydroly | vedclass

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(D) The compound $A$ $(C_{4}H_{8}Cl_{2})$ undergoes hydrolysis at $373 	ext{ K}$ to form a geminal diol,which is unstable and loses a water molecule

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$2,2-$Dichlorobutane and $2-$Butanone

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(D) The compound $A$ $(C_{4}H_{8}Cl_{2})$ undergoes hydrolysis at $373 	ext{ K}$ to form a geminal diol,which is unstable and loses a water molecule to form a carbonyl compound $B$ $(C_{4}H_{8}O)$.Since $B$ reacts with hydroxylamine,it must be an aldehyde or a ketone.Since $B$ does not give Tollen's test,it cannot be an aldehyde; therefore,$B$ must be a ketone.$2,2-$Dichlorobutane on hydrolysis gives $2,2-$butanediol,which loses water to form $2-$butanone $(CH_{3}COCH_{2}CH_{3})$.$2-$Butanone is a ketone,so it reacts with hydroxylamine and does not give Tollen's test.Thus,$A$ is $2,2-$dichlorobutane and $B$ is $2-$butanone.

$A$ $(C_{4}H_{8}Cl_{2})$ $\xrightarrow{\text{Hydrolysis at } 373 \text{ K}}$ $B$ $(C_{4}H_{8}O)$
$B$ reacts with hydroxylamine but does not give Tollen's test. Identify $A$ and $B$.

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$A$ $(C_{4}H_{8}Cl_{2})$ $\xrightarrow{\text{Hydrolysis at } 373 \text{ K}}$ $B$ $(C_{4}H_{8}O)$$B$ reacts with hydroxylamine but does not give Tollen's test. Identify $A$ and $B$.