$(a)$ Derive an expression to find the equivalent resistance of three resistors connected in series. Also, draw the schematic diagram of the circuit.

$(b)$ Find the equivalent resistance of the following circuit

1091-229

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$(a)$ See above articles.

$(b)$ $R _{1}=6 \Omega, R _{2}=10 \Omega, R _{3}=15 \Omega$

Therefore, we have

$\frac{1}{ R _{ P }}=\frac{1}{ R _{1}}+\frac{1}{ R _{2}}+\frac{1}{ R _{3}}=\frac{1}{6}+\frac{1}{10}+\frac{1}{15}$

Or $\frac{1}{ R _{ P }}=\frac{10}{30}=\frac{1}{3}$

Hence, $\quad R_{P}=3 \Omega$

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