2 g of aluminium is treated separately with | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When aluminium is treated with dilute $H_{2}SO_{4}$:$2Al + 3H_{2}SO_{4} ightarrow Al_{2}(SO_{4})_{3} + 3H_{2}$From the stoichiometry,$2 	ext{ m

Vedclass · Accepted Answer

$1:1$

Vedclass · Answer

(B) When aluminium is treated with dilute $H_{2}SO_{4}$:$2Al + 3H_{2}SO_{4} ightarrow Al_{2}(SO_{4})_{3} + 3H_{2}$From the stoichiometry,$2 	ext{ moles of } Al$ produce $3 	ext{ moles of } H_{2}$.When aluminium is treated with $NaOH$:$2Al + 2NaOH + 6H_{2}O ightarrow 2Na[Al(OH)_{4}] + 3H_{2}$From the stoichiometry,$2 	ext{ moles of } Al$ produce $3 	ext{ moles of } H_{2}$.Since the same mass of aluminium $(2 \ g)$ is used in both cases,the number of moles of $Al$ is the same.Therefore,the ratio of the volumes of hydrogen evolved is $3:3$,which simplifies to $1:1$.

$2 \ g$ of aluminium is treated separately with excess of dilute $H_{2}SO_{4}$ and excess of $NaOH$. The ratio of the volumes of hydrogen evolved is

Similar Questions

According to the reaction $6CO_2 + 6H_2O \rightarrow C_6H_{12}O_6 + 6O_2$,how many molecules of $CO_2$ are required to obtain $1.8 \ g$ of glucose? (Molar mass of $C_6H_{12}O_6 = 180 \ g \ mol^{-1}$) $(C = 12, H = 1, O = 16)$

What is the percent atom economy if the formula weight of reactants and the formula weight of products are $45 \ u$ and $35 \ u$ respectively (in $\%$)?

What weight of sodium hydroxide is required to neutralise $100 \ mL$ of $0.1 \ N - HCl$ (in $g$)?

If $2 \ g$ of $NaOH$ is dissolved in water to make a $100 \ cm^3$ solution,what is the normality of this solution?

If $1.5 \, mol$ of oxygen reacts with $Al$ to form $Al_2O_3$,calculate the mass of aluminum used in the reaction in grams.

Vedclass Test Series

Exam Paper Generator

Online Exam Module