(B) Given that $\Delta XYZ \sim \Delta ABC$ for the correspondence $XYZ \leftrightarrow ABC$.By the property of similar triangles,the ratios of their

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(B) Given that $\Delta XYZ \sim \Delta ABC$ for the correspondence $XYZ \leftrightarrow ABC$.By the property of similar triangles,the ratios of their corresponding sides are equal:$\frac{XY}{AB} = \frac{YZ}{BC} = \frac{XZ}{AC}$.We are given that $\frac{XY}{AB} = \frac{3}{5}$.Therefore,$\frac{YZ}{BC} = \frac{3}{5}$.To find $\frac{BC}{YZ}$,we take the reciprocal of both sides:$\frac{BC}{YZ} = \frac{5}{3}$.

Class 10 Mathematics Triangles Mix Examples - Triangles

Medium

$\Delta XYZ \sim \Delta ABC$ for the correspondence $XYZ \leftrightarrow ABC$. If $\frac{XY}{AB} = \frac{3}{5}$,then $\frac{BC}{YZ} = \dots$

A
$\frac{3}{5}$
B
$\frac{5}{3}$
C
$-\frac{3}{5}$
D
$\frac{7}{3}$

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Mix Examples - Triangles

In $\Delta ABC$,$m \angle B = 90^{\circ}$ and $D$ is a point on $\overline{BC}$. Prove that $AD^{2} + BC^{2} = AC^{2} + BD^{2}$.

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In $\Delta XYZ$,$m\angle Y = 90^{\circ}$ and $M$ is the midpoint of $\overline{XZ}$. If $XY = 3$ and $YZ = 4$,then $YM = \ldots$

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Out of the following triplets,$\ldots \ldots \ldots \ldots$ is not a Pythagorean triplet.

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In $\square ABCD$,$\overline{AB} \parallel \overline{CD}$ and $\overline{AC} \cap \overline{BD} = \{M\}$. If $MA = 6$,$MB = 9$ and $MC = 8$,then $MD = \dots$

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$\Delta XYZ \sim \Delta DEF$ for the correspondence $XYZ \leftrightarrow DEF$. If $m \angle X = 50^{\circ}$ and $m \angle Y = 75^{\circ}$,then $m \angle F = \dots$ (in $^{\circ}$)

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$\Delta XYZ \sim \Delta ABC$ for the correspondence $XYZ \leftrightarrow ABC$. If $\frac{XY}{AB} = \frac{3}{5}$,then $\frac{BC}{YZ} = \dots$

Similar Questions

In $\Delta ABC$,$m \angle B = 90^{\circ}$ and $D$ is a point on $\overline{BC}$. Prove that $AD^{2} + BC^{2} = AC^{2} + BD^{2}$.

In $\Delta XYZ$,$m\angle Y = 90^{\circ}$ and $M$ is the midpoint of $\overline{XZ}$. If $XY = 3$ and $YZ = 4$,then $YM = \ldots$

Out of the following triplets,$\ldots \ldots \ldots \ldots$ is not a Pythagorean triplet.

In $\square ABCD$,$\overline{AB} \parallel \overline{CD}$ and $\overline{AC} \cap \overline{BD} = \{M\}$. If $MA = 6$,$MB = 9$ and $MC = 8$,then $MD = \dots$

$\Delta XYZ \sim \Delta DEF$ for the correspondence $XYZ \leftrightarrow DEF$. If $m \angle X = 50^{\circ}$ and $m \angle Y = 75^{\circ}$,then $m \angle F = \dots$ (in $^{\circ}$)

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