(A) square is a quadrilateral where all sides are equal and each interior angle is $90^\circ$.Given that $XYZW$ is a square and the side length $XY =

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(A) square is a quadrilateral where all sides are equal and each interior angle is $90^\circ$.Given that $XYZW$ is a square and the side length $XY = 17 \text{ cm}$.The formula for the area of a square is given by $(\text{side})^2$.Area $= (XY)^2 = 17^2 = 289 \text{ cm}^2$.Therefore,the area of $XYZW$ is $289 \text{ cm}^2$.

Class 9 Mathematics Areas of Parallelograms and Triangles Mix Examples - Areas of Parallelograms and Triangles

Easy

$XYZW$ is a square. If $XY = 17 \text{ cm}$,then find the area of $XYZW$ in $\text{cm}^2$.

A
$289$
B
$128$
C
$336$
D
$36$

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Class 9 Questions

Class 9

Mathematics Questions

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Areas of Parallelograms and Triangles

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Mix Examples - Areas of Parallelograms and Triangles

In the figure,$BD \parallel CA$,$E$ is the mid-point of $CA$,and $BD = \frac{1}{2} CA$. Prove that $\operatorname{ar}(ABC) = 2 \operatorname{ar}(DBC)$.

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$ABCD$ is a parallelogram. If $\operatorname{ar}(ABC) = 42 \, \text{cm}^2$,then find $\operatorname{ar}(ABCD)$ in $\text{cm}^2$.

Medium

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$A$ point $E$ is taken on the side $BC$ of a parallelogram $ABCD$. $AE$ and $DC$ are produced to meet at $F$. Prove that $\operatorname{ar}(\triangle ADF) = \operatorname{ar}(ABFC)$.

Difficult

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In the given figure,$PQM$ is a line and $SQ || RM$. Prove that $ar(PQR) = ar(PMS)$.

Medium

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$ABCD$ is a rectangle. If $AB = 12 \, cm$ and $BC = 7 \, cm$,then find the area of $ABCD$ in $cm^2$.

Easy

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$XYZW$ is a square. If $XY = 17 \text{ cm}$,then find the area of $XYZW$ in $\text{cm}^2$.

Similar Questions

In the figure,$BD \parallel CA$,$E$ is the mid-point of $CA$,and $BD = \frac{1}{2} CA$. Prove that $\operatorname{ar}(ABC) = 2 \operatorname{ar}(DBC)$.

$ABCD$ is a parallelogram. If $\operatorname{ar}(ABC) = 42 \, \text{cm}^2$,then find $\operatorname{ar}(ABCD)$ in $\text{cm}^2$.

$A$ point $E$ is taken on the side $BC$ of a parallelogram $ABCD$. $AE$ and $DC$ are produced to meet at $F$. Prove that $\operatorname{ar}(\triangle ADF) = \operatorname{ar}(ABFC)$.

In the given figure,$PQM$ is a line and $SQ || RM$. Prove that $ar(PQR) = ar(PMS)$.

$ABCD$ is a rectangle. If $AB = 12 \, cm$ and $BC = 7 \, cm$,then find the area of $ABCD$ in $cm^2$.

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