If Delta ABC sim Delta PQR for the correspond | vedclass

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(C) Given that $\Delta ABC \sim \Delta PQR$. Since the triangles are similar,the ratio of their corresponding sides is equal. $\frac{AB}{PQ} = \frac{B

Vedclass · Accepted Answer

$33$

Vedclass · Answer

(C) Given that $\Delta ABC \sim \Delta PQR$. Since the triangles are similar,the ratio of their corresponding sides is equal. $\frac{AB}{PQ} = \frac{BC}{QR} = \frac{AC}{PR} = k$. Given $AB = 5, BC = 7, AC = 10$ and $PR = 15$. Using the ratio $\frac{AC}{PR} = \frac{10}{15} = \frac{2}{3}$. Therefore,the ratio of the sides is $k = \frac{2}{3}$. Now,find the sides of $\Delta PQR$: $PQ = AB 	imes \frac{3}{2} = 5 	imes 1.5 = 7.5$. $QR = BC 	imes \frac{3}{2} = 7 	imes 1.5 = 10.5$. $PR = 15$. Perimeter of $\Delta PQR = PQ + QR + PR = 7.5 + 10.5 + 15 = 33$.

If $\Delta ABC \sim \Delta PQR$ for the correspondence $ABC \leftrightarrow PQR$. If $AB = 5, BC = 7, AC = 10$ and $PR = 15$,the perimeter of $\Delta PQR$ is........

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