$2 \sqrt{3}+\sqrt{3}$ is equal to
$2 \sqrt{6}$
$6$
$3 \sqrt{3}$
$4 \sqrt{6}$
Multiply $5 \sqrt{3}$ and $4 \sqrt{12}$.
Simplify the following:
$(\sqrt{3}-\sqrt{2})^{2}$
Find the value
$(625)^{-\frac{3}{4}}$
For each question, select the proper option from four options given, to make the statement true : (Final answer only)
$0 . \overline{3}=\ldots \ldots . .$
Represent $\sqrt{10}$ on the number line.