The ^{18}O isotope of oxygen will have: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The isotope of oxygen is represented as $^{18}_{8}O$.In this notation,the subscript $8$ represents the atomic number $(Z)$,which is the number of

Vedclass · Accepted Answer

$10$ neutrons and $8$ protons

Vedclass · Answer

(D) The isotope of oxygen is represented as $^{18}_{8}O$.In this notation,the subscript $8$ represents the atomic number $(Z)$,which is the number of protons.The superscript $18$ represents the mass number $(A)$,which is the sum of protons and neutrons $(A = Z + N)$.Therefore,the number of neutrons $(N)$ is calculated as $N = A - Z = 18 - 8 = 10$.Thus,the isotope has $8$ protons and $10$ neutrons.

The $^{18}O$ isotope of oxygen will have:

Similar Questions

The number of protons,neutrons and electrons in ${ }_{71}^{175} Lu$,respectively,are:

Which of the following species are isoelectronic (i.e.,have the same number of electrons)?
$Na^{+}, K^{+}, Mg^{2+}, Ca^{2+}, S^{2-}, Ar$

Which of the following are identical in terms of their atomic number $(Z)$?
$(i)$ $Na$ and $Na^+$
$(ii)$ $F$ and $F^-$

An atom which has lost one electron would be

Calculate the number of protons,neutrons and electrons in $_{35}^{80}Br$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module