CH_3-CH_2-OH xrightarrow{text{Alkaline } KMnO | vedclass

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(B) In the given reaction,ethanol $(CH_3-CH_2-OH)$ is converted into ethanoic acid $(CH_3-COOH)$.This process involves the addition of oxygen to the a

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oxidising agent

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(B) In the given reaction,ethanol $(CH_3-CH_2-OH)$ is converted into ethanoic acid $(CH_3-COOH)$.This process involves the addition of oxygen to the alcohol group.Alkaline $KMnO_4$ (Potassium permanganate) is a strong oxidizing agent that provides oxygen for this oxidation reaction.Therefore,it acts as an oxidising agent.

$CH_3-CH_2-OH \xrightarrow{\text{Alkaline } KMnO_4 + \text{Heat}} CH_3-COOH$
In the above given reaction,alkaline $KMnO_4$ acts as:

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$CH_3-CH_2-OH \xrightarrow{\text{Alkaline } KMnO_4 + \text{Heat}} CH_3-COOH$In the above given reaction,alkaline $KMnO_4$ acts as: