(C) In $\beta$-decay,a neutron in the nucleus is converted into a proton and an electron (the $\beta$-particle) along with an antineutrino. The proces

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Conversion of neutron to proton

(C) In $\beta$-decay,a neutron in the nucleus is converted into a proton and an electron (the $\beta$-particle) along with an antineutrino. The process is represented as: $^1_0n \rightarrow ^1_1p + ^0_{-1}e + \bar{\nu}_e$. Thus,the emission of a $\beta$-particle is caused by the conversion of a neutron to a proton.