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(B) According to the Hardy-Weinberg principle,the frequency of the recessive phenotype is represented by $q^2$.Given that the recessive trait frequenc

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$0.4$

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(B) According to the Hardy-Weinberg principle,the frequency of the recessive phenotype is represented by $q^2$.Given that the recessive trait frequency is $36 \%$,we have $q^2 = 0.36$.Taking the square root of both sides,we get $q = \sqrt{0.36} = 0.6$.Here,$q$ represents the frequency of the recessive allele.The sum of the frequencies of the dominant allele $(p)$ and the recessive allele $(q)$ is $1$,i.e.,$p + q = 1$.Therefore,the frequency of the dominant allele is $p = 1 - q = 1 - 0.6 = 0.4$.Thus,the correct option is $B$.

In a population,$36 \%$ of individuals exhibit the recessive trait. The frequency of the dominant allele in this population is ......

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