Na and Mg crystallize in BCC and FCC type cry | vedclass

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(D) The $BCC$ (Body-Centered Cubic) unit cell consists of $8$ atoms at the corners and $1$ atom at the body center.Number of atoms in $BCC$ $(n)$ = $(

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$2$ and $4$

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(D) The $BCC$ (Body-Centered Cubic) unit cell consists of $8$ atoms at the corners and $1$ atom at the body center.Number of atoms in $BCC$ $(n)$ = $(8 	imes \frac{1}{8}) + 1 = 1 + 1 = 2$.Thus,$Na$ has $2$ atoms per unit cell.The $FCC$ (Face-Centered Cubic) unit cell consists of $8$ atoms at the corners and $1$ atom at each of the $6$ faces.Each face-centered atom is shared by $2$ unit cells.Number of atoms in $FCC$ $(n)$ = $(8 	imes \frac{1}{8}) + (6 	imes \frac{1}{2}) = 1 + 3 = 4$.Thus,$Mg$ has $4$ atoms per unit cell.Therefore,the number of atoms for $Na$ and $Mg$ are $2$ and $4$ respectively.

$Na$ and $Mg$ crystallize in $BCC$ and $FCC$ type crystals respectively,then the number of atoms of $Na$ and $Mg$ present in the unit cell of their respective crystal is

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