40.83 times 1.02 times 1.2 = ? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To solve the expression $40.83 	imes 1.02 	imes 1.2$,we first multiply the numbers as if they were integers:$4083 	imes 102 	imes 12 = 4997592

Vedclass · Accepted Answer

$49.97592$

Vedclass · Answer

(C) To solve the expression $40.83 	imes 1.02 	imes 1.2$,we first multiply the numbers as if they were integers:$4083 	imes 102 	imes 12 = 4997592$Next,we count the total number of decimal places in the original expression:$40.83$ has $2$ decimal places.$1.02$ has $2$ decimal places.$1.2$ has $1$ decimal place.Total decimal places = $2 + 2 + 1 = 5$.Now,place the decimal point in the product $4997592$ such that there are $5$ digits to the right of the decimal point:$49.97592$

$40.83 \times 1.02 \times 1.2 = ?$

Similar Questions

$337.62 + 8.591 + 34.4 = ?$

Evaluate $\frac{0.53 \times 0.53 - 2 \times 0.53 \times 0.41 + 0.41 \times 0.41}{0.53 - 0.41}$

Which of the following numbers is not a factor of $5^{p} 7^{q}$ where $p \neq 0$ and $q \neq 0$?

$4^{11} + 4^{12} + 4^{13} + 4^{14}$ is divisible by:

If $x=\sqrt{\frac{\sqrt{5}+1}{\sqrt{5}-1}},$ then the value of $5x^{2}-5x-1$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module