13 frac{4}{?} + 5 frac{3}{4} text{ of } 3 fra | vedclass

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(C) Let the missing value be $x$.Given equation: $13 \frac{4}{x} + (5 \frac{3}{4} 	ext{ of } 3 \frac{1}{5}) \div 4 \frac{3}{5} = 17 \frac{4}{5}$First

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$5$

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(C) Let the missing value be $x$.Given equation: $13 \frac{4}{x} + (5 \frac{3}{4} 	ext{ of } 3 \frac{1}{5}) \div 4 \frac{3}{5} = 17 \frac{4}{5}$First,solve the 'of' operation: $5 \frac{3}{4} 	ext{ of } 3 \frac{1}{5} = \frac{23}{4} 	imes \frac{16}{5} = \frac{23 	imes 4}{5} = \frac{92}{5} = 18 \frac{2}{5}$.Now,perform the division: $(18 \frac{2}{5}) \div 4 \frac{3}{5} = \frac{92}{5} \div \frac{23}{5} = \frac{92}{5} 	imes \frac{5}{23} = 4$.Substitute this back into the equation: $13 \frac{4}{x} + 4 = 17 \frac{4}{5}$.Subtract $4$ from both sides: $13 \frac{4}{x} = 17 \frac{4}{5} - 4 = 13 \frac{4}{5}$.Comparing the two sides,we get $x = 5$.

$13 \frac{4}{?} + 5 \frac{3}{4} \text{ of } 3 \frac{1}{5} \div 4 \frac{3}{5} = 17 \frac{4}{5}$

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