PCl_5 reacts with propanone to give: | vedclass

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Question

(D) The reaction of $PCl_5$ with a ketone like propanone $(CH_3COCH_3)$ involves the replacement of the carbonyl oxygen atom with two chlorine atoms a

Vedclass · Accepted Answer

gem-dichloride

Vedclass · Answer

(D) The reaction of $PCl_5$ with a ketone like propanone $(CH_3COCH_3)$ involves the replacement of the carbonyl oxygen atom with two chlorine atoms at the same carbon position.This results in the formation of a $gem$-dichloride (specifically $2,2$-dichloropropane).The reaction is: $CH_3COCH_3 + PCl_5 	o CH_3-CCl_2-CH_3 + POCl_3$.

$PCl_5$ reacts with propanone to give:

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