Find the missing number in the series: 4000, | vedclass

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Question

(B) The pattern of the series is based on the difference between consecutive terms being halved.$4000 - 2008 = 1992$; $1992 / 2 = 996$$2008 - 1012 = 9

Vedclass · Accepted Answer

$514$

Vedclass · Answer

(B) The pattern of the series is based on the difference between consecutive terms being halved.$4000 - 2008 = 1992$; $1992 / 2 = 996$$2008 - 1012 = 996$; $996 / 2 = 498$$1012 - x = 498 \implies x = 1012 - 498 = 514$$514 - 265 = 249$; $249 / 2 = 124.5$$265 - 140.5 = 124.5$; $124.5 / 2 = 62.25$$140.5 - 78.25 = 62.25$; $62.25 / 2 = 31.125$Thus,the missing number is $514$.

$8$	$8$	$12$	$24$
$36$	$(a)$	$(b)$	$(c)$	$(d)$	$(e)$

$6$	$10$	$32$	$126$
$2$	$(a)$	$(b)$	$(c)$

Find the missing number in the series: $4000, 2008, 1012, ?, 265, 140.5, 78.25$.

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