7, 36, 125, 256, ?, 64, 1 | vedclass

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Question

(D) The given series follows the pattern $n^{(8-n)}$ where $n$ is the position of the term starting from $n=1$ to $n=7$.For $n=1$: $1^{(8-1)} = 1^7 =

Vedclass · Accepted Answer

$243$

Vedclass · Answer

(D) The given series follows the pattern $n^{(8-n)}$ where $n$ is the position of the term starting from $n=1$ to $n=7$.For $n=1$: $1^{(8-1)} = 1^7 = 1$ (Wait,the series is given as $7, 36, 125, 256, ?, 64, 1$).Let us re-examine the pattern: $7^1=7, 6^2=36, 5^3=125, 4^4=256, 3^5=?, 2^6=64, 1^7=1$.Calculating the missing term:$3^5 = 3 	imes 3 	imes 3 	imes 3 	imes 3 = 243$.Therefore,the missing number is $243$.

$4$	$29$	$74$	$231$	$928$	$4641$
$3$	$(A)$	$(B)$	$(C)$	$(D)$	$(E)$

$7, 36, 125, 256, ?, 64, 1$

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