3, 4, 7, 7, 13, 13, 21, 22, 31, 34, ? | vedclass

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Question

(B) The given sequence is a combination of two alternating series:Series $(i)$ consists of the $1^{st}, 3^{rd}, 5^{th}, 7^{th}, 9^{th}$ terms: $3, 7,

Vedclass · Accepted Answer

$43$

Vedclass · Answer

(B) The given sequence is a combination of two alternating series:Series $(i)$ consists of the $1^{st}, 3^{rd}, 5^{th}, 7^{th}, 9^{th}$ terms: $3, 7, 13, 21, 31, ...$Pattern for Series $(i)$: $3 (+4) = 7, 7 (+6) = 13, 13 (+8) = 21, 21 (+10) = 31$.The next term in this series would be $31 (+12) = 43$.Series $(ii)$ consists of the $2^{nd}, 4^{th}, 6^{th}, 8^{th}, 10^{th}$ terms: $4, 7, 13, 22, 34, ...$Pattern for Series $(ii)$: $4 (+3) = 7, 7 (+6) = 13, 13 (+9) = 22, 22 (+12) = 34$.Since the question mark represents the $11^{th}$ term,it follows the pattern of Series $(i)$.Therefore,the missing number is $31 + 12 = 43$.

$3, 4, 7, 7, 13, 13, 21, 22, 31, 34, ?$

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