1, 9, 25, 49, 81, ? | vedclass

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Question

(C) The given series is a sequence of squares of consecutive odd numbers:$1^{2} = 1$$3^{2} = 9$$5^{2} = 25$$7^{2} = 49$$9^{2} = 81$Following this patt

Vedclass · Accepted Answer

$121$

Vedclass · Answer

(C) The given series is a sequence of squares of consecutive odd numbers:$1^{2} = 1$$3^{2} = 9$$5^{2} = 25$$7^{2} = 49$$9^{2} = 81$Following this pattern,the next odd number is $11$,and its square is $11^{2} = 121$.

$264$	$136$	$72$	$40$
$488$	$(a)$	$(b)$	$(c)$

$1, 9, 25, 49, 81, ?$

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