sqrt[3]{(13.608)^{2}-(13.392)^{2}} is equal t | vedclass

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Question

(C) The given expression is $\sqrt[3]{(13.608)^{2}-(13.392)^{2}}$.Using the algebraic identity $a^{2}-b^{2}=(a+b)(a-b)$,we have:$= \sqrt[3]{(13.608+13

Vedclass · Accepted Answer

$1.8$

Vedclass · Answer

(C) The given expression is $\sqrt[3]{(13.608)^{2}-(13.392)^{2}}$.Using the algebraic identity $a^{2}-b^{2}=(a+b)(a-b)$,we have:$= \sqrt[3]{(13.608+13.392) 	imes (13.608-13.392)}$$= \sqrt[3]{(27) 	imes (0.216)}$$= \sqrt[3]{27} 	imes \sqrt[3]{0.216}$$= \sqrt[3]{3^{3}} 	imes \sqrt[3]{(0.6)^{3}}$$= 3 	imes 0.6 = 1.8$.

$\sqrt[3]{(13.608)^{2}-(13.392)^{2}}$ is equal to

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