$3 \frac{1}{4} + 2 \frac{1}{2} - 1 \frac{5}{6} = \frac{(?)^{2}}{10} + 1 \frac{5}{12}$

  • A
    $25$
  • B
    $\sqrt{5}$
  • C
    $625$
  • D
    $5$

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Similar Questions

The value of $\frac{1}{a^{2}+a x+x^{2}}-\frac{1}{a^{2}-a x+x^{2}}+\frac{2 a x}{a^{4}+a^{2} x^{2}+x^{4}}$ is

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$\frac{3 \sqrt{2}}{\sqrt{6}-\sqrt{3}}-\frac{4 \sqrt{3}}{\sqrt{6}-\sqrt{2}}-\frac{6}{\sqrt{8}+\sqrt{12}}=?$

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$11 \frac{1}{3} \times 4 \frac{8}{10} \div ? = 22 \frac{2}{3}$

What should come in place of the question mark $(?)$ in the following equation?
$39.97 \%$ of $649.8 \div 13.05 = 45.12 - ?$

$4^{11} + 4^{12} + 4^{13} + 4^{14}$ is divisible by:

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