frac{1}{3} + frac{1}{2} + frac{1}{x} = 4. The | vedclass

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Question

(B) Given equation: $\frac{1}{3} + \frac{1}{2} + \frac{1}{x} = 4$First,find the sum of the fractions $\frac{1}{3}$ and $\frac{1}{2}$:$\frac{1}{3} + \f

Vedclass · Accepted Answer

$\frac{6}{19}$

Vedclass · Answer

(B) Given equation: $\frac{1}{3} + \frac{1}{2} + \frac{1}{x} = 4$First,find the sum of the fractions $\frac{1}{3}$ and $\frac{1}{2}$:$\frac{1}{3} + \frac{1}{2} = \frac{2 + 3}{6} = \frac{5}{6}$Substitute this back into the equation:$\frac{5}{6} + \frac{1}{x} = 4$Isolate $\frac{1}{x}$:$\frac{1}{x} = 4 - \frac{5}{6}$Convert $4$ to a fraction with denominator $6$:$\frac{1}{x} = \frac{24}{6} - \frac{5}{6} = \frac{19}{6}$Taking the reciprocal of both sides:$x = \frac{6}{19}$

$\frac{1}{3} + \frac{1}{2} + \frac{1}{x} = 4$. Then $x = ?$

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