$(\sqrt{4489}-\sqrt{2601})=(?)^{2}$

$7 \%$ of $4000 - 12 \%$ of $550$

$N$ is the largest two-digit number which,when divided by $3, 4,$ and $6,$ leaves the remainders $1, 2,$ and $4$ respectively. What is the remainder when $N$ is divided by $5$?

If $30 \%$ of a number is $190.8$,what will be $175 \%$ of that number?

The least positive integer that should be subtracted from $3011 \times 3012$ so that the difference is a perfect square,is

How many numbers between $100$ and $300$ are divisible by $11$?