2, cm of rain has fallen on a 1, km^2 of land | vedclass

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(C) Total volume of rain water = Area $	imes$ height.Given,Area = $1\, km^2 = (1000\, m)^2 = 1,000,000\, m^2$.Height = $2\, cm = 0.02\, m$.Total volu

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$10$

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(C) Total volume of rain water = Area $	imes$ height.Given,Area = $1\, km^2 = (1000\, m)^2 = 1,000,000\, m^2$.Height = $2\, cm = 0.02\, m$.Total volume = $1,000,000\, m^2 	imes 0.02\, m = 20,000\, m^3$.Volume of collected water = $50\%$ of $20,000\, m^3 = 0.5 	imes 20,000 = 10,000\, m^3$.Base area of the pool = $100\, m 	imes 10\, m = 1,000\, m^2$.Increase in water level = $\frac{	ext{Volume collected}}{	ext{Base area of pool}} = \frac{10,000\, m^3}{1,000\, m^2} = 10\, m$.Therefore,the water level in the pool would have increased by $10\, m$.

$2\, cm$ of rain has fallen on a $1\, km^2$ of land. Assuming that $50\%$ of the raindrops could have been collected and contained in a pool having a $100\, m \times 10\, m$ base,by what level would the water level in the pool have increased? (in $m$)

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