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Question

(A) Let the distance between two consecutive trees be $d$.The number of gaps between the $13^{th}$ tree and the $34^{th}$ tree is $(34 - 13) = 21$ gap

Vedclass · Accepted Answer

$42$

Vedclass · Answer

(A) Let the distance between two consecutive trees be $d$.The number of gaps between the $13^{th}$ tree and the $34^{th}$ tree is $(34 - 13) = 21$ gaps.Distance covered in $18 \, seconds = 21d$.Speed of the car $= \frac{	ext{Distance}}{	ext{Time}} = \frac{21d}{18} = \frac{7d}{6} \, 	ext{units/second}$.The number of gaps between the $1^{st}$ tree and the $50^{th}$ tree is $(50 - 1) = 49$ gaps.Total distance to cover $= 49d$.Time taken $= \frac{	ext{Total Distance}}{	ext{Speed}} = \frac{49d}{7d/6} = 49 	imes \frac{6}{7} = 7 	imes 6 = 42 \, seconds$.

$50$ trees are standing in a line such that the distance between any two consecutive trees is the same. $A$ car takes $18 \, seconds$ to travel from the $13^{th}$ tree to the $34^{th}$ tree. How much time (in $seconds$) will it take to reach from the first tree to the $50^{th}$ tree?

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