(B) For $A$ (Simple Interest):$SI = \frac{P \times R \times T}{100} = \frac{6000 \times 5 \times 2}{100} = Rs. 600$.For $B$ (Compound Interest):Amount

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(B) For $A$ (Simple Interest):$SI = \frac{P \times R \times T}{100} = \frac{6000 \times 5 \times 2}{100} = Rs. 600$.For $B$ (Compound Interest):Amount $= P \left(1 + \frac{R}{100}\right)^n = 5000 \left(1 + \frac{8}{100}\right)^2 = 5000 \left(\frac{108}{100}\right)^2 = 5000 \times 1.1664 = Rs. 5832$.$CI = \text{Amount} - P = 5832 - 5000 = Rs. 832$.Difference between their interests $= 832 - 600 = Rs. 232$.

Competitive Quantitative Aptitude Interest Compound Interest

Medium

$A$ deposited $Rs. 6000$ in a bank at $5 \%$ per annum simple interest. $B$ deposited $Rs. 5000$ at $8 \%$ $p.a.$ compound interest. After $2$ years,the difference between their interests (in $Rs.$) will be:

A
$230$
B
$232$
C
$600$
D
$832$

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Interest

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Compound Interest

$A$ sum of money lent at compound interest amounts to ₹ $1460$ in $2$ years and to ₹ $1606$ in $3$ years. The rate of interest (in $\%$) per annum is:

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$A$ sum of money invested at compound interest amounts to ₹ $800$ in $3$ years and to ₹ $840$ in $4$ years. The rate of interest (in $\%$) per annum is

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$A$ deposited $Rs. 6000$ in a bank at $5 \%$ per annum simple interest. $B$ deposited $Rs. 5000$ at $8 \%$ $p.a.$ compound interest. After $2$ years,the difference between their interests (in $Rs.$) will be:

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$A$ sum of money lent at compound interest amounts to ₹ $1460$ in $2$ years and to ₹ $1606$ in $3$ years. The rate of interest (in $\%$) per annum is:

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