11^{th} October 1986 was a Saturday. In which | vedclass

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(D) To find when the same calendar repeats,we calculate the number of odd days. $A$ normal year has $1$ odd day and a leap year has $2$ odd days.From

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None of these

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(D) To find when the same calendar repeats,we calculate the number of odd days. $A$ normal year has $1$ odd day and a leap year has $2$ odd days.From $1986$ to $1997$,the total number of odd days is calculated as follows:$1986$ (normal): $1$ odd day$1987$ (normal): $1$ odd day$1988$ (leap): $2$ odd days$1989$ (normal): $1$ odd day$1990$ (normal): $1$ odd day$1991$ (normal): $1$ odd day$1992$ (leap): $2$ odd days$1993$ (normal): $1$ odd day$1994$ (normal): $1$ odd day$1995$ (normal): $1$ odd day$1996$ (leap): $2$ odd daysSum of odd days = $1+1+2+1+1+1+2+1+1+1+2 = 14$. Since $14$ is divisible by $7$,the remainder is $0$.Therefore,the calendar for $1997$ will be the same as $1986$. Since $1997$ is not in the options,the correct answer is 'None of these'.

$11^{th}$ October $1986$ was a Saturday. In which year will the same day and same month fall on a Saturday again?

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