2 men and 4 boys can do a piece of work in 10 | vedclass

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(B) Let the efficiency of a man be $m$ and a boy be $b$.Given that $(2m + 4b) 	imes 10 = (4m + 5b) 	imes 6$.Expanding the equation: $20m + 40b = 24m

Vedclass · Accepted Answer

$5:2$

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(B) Let the efficiency of a man be $m$ and a boy be $b$.Given that $(2m + 4b) 	imes 10 = (4m + 5b) 	imes 6$.Expanding the equation: $20m + 40b = 24m + 30b$.Rearranging the terms: $40b - 30b = 24m - 20m$.This simplifies to $10b = 4m$,or $2m = 5b$.Since wages are paid according to output (efficiency),the ratio of wages is equal to the ratio of their daily work output.Given the daily wage of a man is $Rs. 40$,we have $2 	imes 40 = 5b$.$80 = 5b$,which gives $b = 16$.The ratio of daily wages of a man to a boy is $40 : 16$.Dividing both by $8$,we get $5 : 2$.

$2$ men and $4$ boys can do a piece of work in $10$ days,while $4$ men and $5$ boys can do it in $6$ days. Men and boys are paid wages according to their output. If the daily wage of a man is $Rs. 40$,then the ratio of daily wages of a man and a boy will be

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