(D) Let $1$ man's $1 \, \text{day}$ work be $M$ and $1$ woman's $1 \, \text{day}$ work be $W$.Total work = $28 \times 15 \times M = 15 \times 24 \time

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(D) Let $1$ man's $1 \, \text{day}$ work be $M$ and $1$ woman's $1 \, \text{day}$ work be $W$.Total work = $28 \times 15 \times M = 15 \times 24 \times W$.$28 M = 24 W \implies \frac{M}{W} = \frac{24}{28} = \frac{6}{7}$.Work done by $30$ men in $1 \, \text{day} = 30 M$.Work done by $18$ women in $1 \, \text{day} = 18 W$.Ratio = $\frac{30 M}{18 W} = \frac{30}{18} \times \frac{M}{W} = \frac{5}{3} \times \frac{6}{7} = \frac{5 \times 2}{7} = \frac{10}{7}$.Thus,the ratio is $10:7$.

Competitive Quantitative Aptitude Time and Work and Wages Time and Work

Medium

$28$ men can complete a piece of work in $15 \, \text{days}$ and $15$ women can complete the same piece of work in $24 \, \text{days}$. What is the respective ratio between the amount of work done by $30$ men in $1 \, \text{day}$ and the amount of work done by $18$ women in $1 \, \text{day}$?

A
$4:7$
B
$9:15$
C
$3:5$
D
$10:7$

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Time and Work and Wages

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Time and Work

$P$ and $Q$ working together can complete a certain work in $6 \, \text{days}$. $Q$ alone can do it in $8 \, \text{days}$. In how many $\text{days}$ could $P$ alone finish the same work?

Easy

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$A$ certain number of men complete a work in $160\, days$. If there were $38\, men$ more, the work could be finished in $20\, days$ less. How many men were originally there?

Easy

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If $3$ men and $4$ boys can earn $Rs. 2100$ in $7$ days,and $11$ men and $13$ boys can earn $Rs. 8300$ in $8$ days,in what time will $7$ men and $9$ boys earn $Rs. 11000$? (in days)

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$P$ can complete a work in $12$ days working $8$ hours a day. $Q$ can complete the same work in $8$ days working $10$ hours a day. If both $P$ and $Q$ work together,working $8$ hours a day,in how many days can they complete the work?

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$A$ can do a piece of work in $20$ days and $B$ in $30$ days. They work together for $7$ days and then both leave the work. Then $C$ alone finishes the remaining work in $10$ days. In how many days will $C$ finish the full work?

Medium

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$28$ men can complete a piece of work in $15 \, \text{days}$ and $15$ women can complete the same piece of work in $24 \, \text{days}$. What is the respective ratio between the amount of work done by $30$ men in $1 \, \text{day}$ and the amount of work done by $18$ women in $1 \, \text{day}$?

Similar Questions

$P$ and $Q$ working together can complete a certain work in $6 \, \text{days}$. $Q$ alone can do it in $8 \, \text{days}$. In how many $\text{days}$ could $P$ alone finish the same work?

$A$ certain number of men complete a work in $160\, days$. If there were $38\, men$ more, the work could be finished in $20\, days$ less. How many men were originally there?

If $3$ men and $4$ boys can earn $Rs. 2100$ in $7$ days,and $11$ men and $13$ boys can earn $Rs. 8300$ in $8$ days,in what time will $7$ men and $9$ boys earn $Rs. 11000$? (in days)

$P$ can complete a work in $12$ days working $8$ hours a day. $Q$ can complete the same work in $8$ days working $10$ hours a day. If both $P$ and $Q$ work together,working $8$ hours a day,in how many days can they complete the work?

$A$ can do a piece of work in $20$ days and $B$ in $30$ days. They work together for $7$ days and then both leave the work. Then $C$ alone finishes the remaining work in $10$ days. In how many days will $C$ finish the full work?

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