A can complete a piece of work in 40 days. He | vedclass

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(A) Work done by $A$ in $5$ days $= \frac{5}{40} = \frac{1}{8}$.Remaining work $= 1 - \frac{1}{8} = \frac{7}{8}$.$B$ completes $\frac{7}{8}$ of the wo

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$15$

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(A) Work done by $A$ in $5$ days $= \frac{5}{40} = \frac{1}{8}$.Remaining work $= 1 - \frac{1}{8} = \frac{7}{8}$.$B$ completes $\frac{7}{8}$ of the work in $21$ days.Therefore,$B$ would complete the whole work in $\frac{21 	imes 8}{7} = 24$ days.Now,$A$ takes $40$ days and $B$ takes $24$ days to complete the work individually.Working together,$A$ and $B$ would complete the work in $\frac{x 	imes y}{x + y}$ days,where $x = 40$ and $y = 24$.Time taken $= \frac{40 	imes 24}{40 + 24} = \frac{960}{64} = 15$ days.

$A$ can complete a piece of work in $40$ days. He starts working,but having some other engagements,he leaves after $5$ days. Thereafter,$B$ completes the remaining work in $21$ days. How many days would $A$ and $B$ take to complete this work working together?

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