10 men can complete a piece of work in 15 day | vedclass

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(A) Let the work done by $10$ men be represented by $X = 15$ days.Let the work done by $15$ women be represented by $Y = 12$ days.Since the group of $

Vedclass · Accepted Answer

$6 \frac{2}{3}$

Vedclass · Answer

(A) Let the work done by $10$ men be represented by $X = 15$ days.Let the work done by $15$ women be represented by $Y = 12$ days.Since the group of $10$ men and the group of $15$ women are working together,we use the formula for combined work time: $	ext{Time} = \frac{X 	imes Y}{X + Y}$.Substituting the values: $	ext{Time} = \frac{15 	imes 12}{15 + 12}$.$	ext{Time} = \frac{180}{27}$.Dividing both numerator and denominator by $9$,we get $\frac{20}{3}$ days.Converting to a mixed fraction,we get $6 \frac{2}{3}$ days.

$10$ men can complete a piece of work in $15$ days and $15$ women can complete the same work in $12$ days. If all the $10$ men and $15$ women work together,in how many days will the work be completed?

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