A and B can do a work in 8 days,B and C can d | vedclass

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(C) Work done per day by $(A + B) = \frac{1}{8}$.Work done per day by $(B + C) = \frac{1}{12}$.Work done per day by $(A + B + C) = \frac{1}{6}$.To fin

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$8$

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(C) Work done per day by $(A + B) = \frac{1}{8}$.Work done per day by $(B + C) = \frac{1}{12}$.Work done per day by $(A + B + C) = \frac{1}{6}$.To find the work done by $(A + C)$,we first find the work done by $B$ alone:Work done by $B = (A + B + C) - (A + C)$ is not direct,so we use:Work done by $B = (A + B) + (B + C) - (A + B + C) = \frac{1}{8} + \frac{1}{12} - \frac{1}{6} = \frac{3 + 2 - 4}{24} = \frac{1}{24}$.Now,work done by $A = (A + B) - B = \frac{1}{8} - \frac{1}{24} = \frac{3 - 1}{24} = \frac{2}{24} = \frac{1}{12}$.Work done by $C = (B + C) - B = \frac{1}{12} - \frac{1}{24} = \frac{2 - 1}{24} = \frac{1}{24}$.Work done by $(A + C)$ per day $= \frac{1}{12} + \frac{1}{24} = \frac{2 + 1}{24} = \frac{3}{24} = \frac{1}{8}$.Therefore,$A$ and $C$ together will complete the work in $8$ days.

$A$ and $B$ can do a work in $8$ days,$B$ and $C$ can do the same work in $12$ days. $A, B$ and $C$ together can finish it in $6$ days. $A$ and $C$ together will do it in (in days):

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