(B) Let the work done by $(P+Q)$,$(Q+R)$,and $(R+P)$ in one day be $\frac{1}{30}$,$\frac{1}{40}$,and $\frac{1}{60}$ respectively.Adding these,we get $

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(B) Let the work done by $(P+Q)$,$(Q+R)$,and $(R+P)$ in one day be $\frac{1}{30}$,$\frac{1}{40}$,and $\frac{1}{60}$ respectively.Adding these,we get $2(P+Q+R) = \frac{1}{30} + \frac{1}{40} + \frac{1}{60}$.$2(P+Q+R) = \frac{4+3+2}{120} = \frac{9}{120} = \frac{3}{40}$.Therefore,$(P+Q+R)$ together can do the work in $2 \times \frac{40}{3} = \frac{80}{3} \, days$.

Competitive Quantitative Aptitude Time and Work and Wages Time and Work

Medium

$P$ and $Q$ complete a certain work in $30 \, days$,$Q$ and $R$ in $40 \, days$,while $R$ and $P$ in $60 \, days$. How long will they take to finish it together? (in $days$)

A
$\frac{40}{3}$
B
$\frac{80}{3}$
C
$\frac{160}{3}$
D
$\frac{20}{3}$

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Time and Work and Wages

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Time and Work

Sixteen men can complete a work in $15$ days,$24$ children can do the same work in $20$ days. In how many days will $8$ men and $8$ children complete the same work?

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$3$ men and $2$ women can do a piece of work in $15$ days. $2$ men and $3$ women can do the same work in $18$ days. The number of days to be taken by $1$ man and $1$ woman to do the work is:

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$6$ men or $12$ women can do a piece of work in $20$ days. In how many days can $8$ men and $16$ women do twice as big as this work?

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$A$ and $B$ working separately can do a piece of work in $9$ and $12$ days,respectively. If they work for a day alternatively with $A$ beginning,the work would be completed in (in days):

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$7$ men can complete a piece of work in $12$ days. How many additional men will be required to complete double the work in $8$ days?

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$P$ and $Q$ complete a certain work in $30 \, days$,$Q$ and $R$ in $40 \, days$,while $R$ and $P$ in $60 \, days$. How long will they take to finish it together? (in $days$)

Similar Questions

Sixteen men can complete a work in $15$ days,$24$ children can do the same work in $20$ days. In how many days will $8$ men and $8$ children complete the same work?

$3$ men and $2$ women can do a piece of work in $15$ days. $2$ men and $3$ women can do the same work in $18$ days. The number of days to be taken by $1$ man and $1$ woman to do the work is:

$6$ men or $12$ women can do a piece of work in $20$ days. In how many days can $8$ men and $16$ women do twice as big as this work?

$A$ and $B$ working separately can do a piece of work in $9$ and $12$ days,respectively. If they work for a day alternatively with $A$ beginning,the work would be completed in (in days):

$7$ men can complete a piece of work in $12$ days. How many additional men will be required to complete double the work in $8$ days?

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