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(C) When $HCl$ gas is passed through the solution,the concentration of $Cl^{-}$ ions increases significantly due to the dissociation of $HCl$.Accordin

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Only $NaCl$

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(C) When $HCl$ gas is passed through the solution,the concentration of $Cl^{-}$ ions increases significantly due to the dissociation of $HCl$.According to the common ion effect,the ionic product of $NaCl$ $([Na^{+}][Cl^{-}])$ exceeds its solubility product $(K_{sp})$.Since $NaCl$ has a lower solubility compared to $MgCl_{2}$ and $CaCl_{2}$ in the presence of high $Cl^{-}$ concentration,$NaCl$ crystallizes out of the solution.$MgCl_{2}$ and $CaCl_{2}$ remain in the solution as they are more soluble.

$HCl$ gas was passed through a solution containing $CaCl_{2}$,$MgCl_{2}$,and $NaCl$. Which of the following compound$(s)$ crystallise$(s)$?

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