80 text{ litre} mixture of milk and water con | vedclass

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(C) Initial volume of mixture $= 80 	ext{ litres}$.Milk content $= 10 \% 	ext{ of } 80 = 8 	ext{ litres}$.Water content $= 80 - 8 = 72 	ext{ litre

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$10$

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(C) Initial volume of mixture $= 80 	ext{ litres}$.Milk content $= 10 \% 	ext{ of } 80 = 8 	ext{ litres}$.Water content $= 80 - 8 = 72 	ext{ litres}$.Let $x$ be the amount of milk added.In the new mixture,the amount of water remains $72 	ext{ litres}$,which represents $80 \%$ of the new total volume.Let the new total volume be $V$.$0.80 	imes V = 72 \implies V = \frac{72}{0.80} = 90 	ext{ litres}$.The amount of milk added $= V - 80 = 90 - 80 = 10 	ext{ litres}$.

$80 \text{ litre}$ mixture of milk and water contains $10 \%$ milk. How much milk (in $\text{litre}$) must be added to make water percentage in the mixture $80 \% ?$

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