0.5 g of hydrocarbon gave 0.9 g of water on | vedclass

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(B) The mass of $H_2O$ produced is $0.9 \ g$. The mass of hydrogen in $0.9 \ g$ of $H_2O$ is calculated as: $	ext{Mass of } H = \frac{2}{18} 	imes 0

Vedclass · Accepted Answer

$80$

Vedclass · Answer

(B) The mass of $H_2O$ produced is $0.9 \ g$. The mass of hydrogen in $0.9 \ g$ of $H_2O$ is calculated as: $	ext{Mass of } H = \frac{2}{18} 	imes 0.9 \ g = 0.1 \ g$. The percentage of hydrogen in the hydrocarbon is: $\frac{0.1 \ g}{0.5 \ g} 	imes 100 = 20 \%$. Since the compound is a hydrocarbon (containing only carbon and hydrogen),the percentage of carbon is $100 \% - 20 \% = 80 \%$. Therefore,the correct option is $B$.

$0.5 \ g$ of hydrocarbon gave $0.9 \ g$ of water on combustion. The percentage of carbon in the hydrocarbon is:

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