4.0 , g of caustic soda is dissolved in 100 , | vedclass

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Question

(A) The formula for normality $(N)$ is given by: $N = \frac{	ext{mass of solute (g)}}{	ext{equivalent mass} 	imes 	ext{volume of solution (L)}}$.C

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(A) The formula for normality $(N)$ is given by: $N = \frac{	ext{mass of solute (g)}}{	ext{equivalent mass} 	imes 	ext{volume of solution (L)}}$.Caustic soda is $NaOH$. Its molar mass is $40 \, g/mol$. Since $NaOH$ is a monoacidic base,its equivalent mass is equal to its molar mass,which is $40 \, g/eq$.Given: Mass of $NaOH = 4.0 \, g$,Volume of solution = $100 \, mL = 0.1 \, L$.Substituting the values: $N = \frac{4.0}{40 	imes 0.1} = \frac{4.0}{4.0} = 1 \, N$.Therefore,the correct option is $A$.

$4.0 \, g$ of caustic soda is dissolved in $100 \, mL$ of solution. The normality of the solution is: (in $, N$)

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