$0.126 \ g$ of an acid requires $20 \ mL$ of $0.1 \ N$ $NaOH$ for complete neutralization. The equivalent weight of the acid is:

$0.1914 \ g$ of an organic acid is dissolved in approx. $20 \ mL$ of water. $25 \ mL$ of $0.12 \ N$ $NaOH$ is required for the complete neutralization of the acid solution. The equivalent weight of the acid is

$A$ metal oxide is reduced by heating it in a stream of hydrogen. It is found that after complete reduction,$3.15 \, g$ of the oxide yielded $1.05 \, g$ of the metal. We may deduce that:

$1.5 \ g$ of $CdCl_2$ was found to contain $0.9 \ g$ of $Cd$. Calculate the atomic weight of $Cd$.

If $74.5 \ g$ of a metallic chloride contains $35.5 \ g$ of chlorine,then the equivalent mass of the metal will be ...... .

$A$ metal $(M)$ forms two oxides. The ratio $M:O$ (by weight) in the two oxides are $25:4$ and $25:6$. The minimum value of atomic mass of $M$ is