Match the reactants in Column-$I$ with their products in Column-$II$.
Column-$I$ (Reactants)Column-$II$ (Products)
$A$. $H_2C=CH_2 + Br_2 \xrightarrow{CCl_4}$$i$. $CH_3CH_2CH_2Br$
$B$. $CH_3CH=CH_2 + HI \rightarrow$$ii$. $BrCH_2-CH_2Br$
$C$. $C_6H_5N_2^+X^- + KI \rightarrow$$iii$. $CH_3CHICH_3$
$D$. $CH_3CH=CH_2 + HBr \xrightarrow{peroxide}$$iv$. $C_6H_5I$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A-II, B-III, C-IV, D-I) The reactions are matched as follows:
$A$. $H_2C=CH_2 + Br_2 \xrightarrow{CCl_4} BrCH_2-CH_2Br$ (Vicinal dihalide formation) $\rightarrow ii$
$B$. $CH_3CH=CH_2 + HI \rightarrow CH_3CHICH_3$ (Markovnikov addition) $\rightarrow iii$
$C$. $C_6H_5N_2^+X^- + KI \rightarrow C_6H_5I + N_2 + KX$ (Sandmeyer-type reaction) $\rightarrow iv$
$D$. $CH_3CH=CH_2 + HBr \xrightarrow{peroxide} CH_3CH_2CH_2Br$ (Anti-Markovnikov addition) $\rightarrow i$
Therefore,the correct matching is: $A-ii, B-iii, C-iv, D-i$.

Explore More

Similar Questions

Match the type of reaction given in Column-$I$ with the reaction in Column-$II$.
Column-$I$ (Reactants)Column-$II$ (Type of Reaction)
$(A)$ $C_6H_5NH_2 \xrightarrow{NaNO_2, HX, 273-278 K} C_6H_5N_2^+X^-$$(i)$ Wurtz-Fittig reaction
$(B)$ $C_6H_5N_2^+X^- \xrightarrow{Cu_2X_2} C_6H_5X$$(ii)$ Diazotization
$(C)$ $C_6H_6 + 2Na + RX \xrightarrow{\text{dry ether}} C_6H_5R$$(iii)$ Sandmeyer reaction
$(D)$ $2C_6H_6 + 2Na \xrightarrow{\text{dry ether}} C_6H_5-C_6H_5$$(iv)$ Fittig reaction

The product $A$ is
$4-methylcyclohexyl bromide + OH^- \xrightarrow{S_N2} A$

What is the product of the reaction?

Difficult
View Solution

What is the major product obtained in the following reaction?

Difficult
View Solution

$A$ (organic compound) $+ O_2 \to X + Y + Z$. Compound $(A)$ in pure form does not give a precipitate with $AgNO_3$ solution. $A$ mixture containing $70\%$ of $(A)$ and $30\%$ of ether is used as an anaesthetic. Compound $(X)$ and $(Y)$ are oxides while $(Z)$ is a pungent smelling gas. $(X)$ is a neutral oxide which turns cobalt chloride paper pink. Compound $(Y)$ turns lime water milky and produces an acidic solution with water. Compounds $(A), (X), (Y)$ and $(Z)$ respectively will be:

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo