(C) The reduction of $Cu^{2+}$ to $Cu^{+}$ occurs when $Cu^{2+}$ reacts with iodide ions $(I^-)$ because $CuI$ is insoluble and the reaction is thermo

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(C) The reduction of $Cu^{2+}$ to $Cu^{+}$ occurs when $Cu^{2+}$ reacts with iodide ions $(I^-)$ because $CuI$ is insoluble and the reaction is thermodynamically favorable.The balanced chemical equation is: $2Cu^{2+} + 4I^- \to 2CuI(s) + I_2(s)$.

Class 12 Chemistry d-and f-Block Elements Chemical properties

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$Cu^{2+}$ ions will be reduced to $Cu^{+}$ ions by the addition of an aqueous solution of

AIIMS 1992 All AIIMS

A
$KF$
B
$KCl$
C
$KI$
D
$KOH$

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d-and f-Block Elements

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Chemical properties

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Consider the following transformation:
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Iodine is formed when $KI$ reacts with a solution of

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$Cu^{2+}$ ions will be reduced to $Cu^{+}$ ions by the addition of an aqueous solution of

Similar Questions

Which is a stronger reducing agent,$Cr^{2+}$ or $Fe^{2+}$,and why?

Consider the following transformation:$2CuX_2 \xrightarrow{\text{Room temperature}} 2CuX + X_2 \uparrow$Then $X^-$ can be:

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Consider the following transformation:
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