Indicate the dipole moment arrow for the following molecules:
$(i)$ $HF$
$(ii)$ $CO$
$(iii)$ $Cl_2$

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(N/A) The dipole moment arrow points from the less electronegative atom to the more electronegative atom.
$(i)$ $H \xrightarrow{\quad} F$ (Since $F$ is more electronegative than $H$)
$(ii)$ $C \xrightarrow{\quad} O$ (Since $O$ is more electronegative than $C$)
$(iii)$ $Cl-Cl$ (No dipole moment as both atoms have the same electronegativity,so the net dipole moment is $0$)

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Which bond is more polar in the following pairs of molecules: $(a)$ $H_3C-H, H_3C-Br$ $(b)$ $H_3C-NH_2, H_3C-OH$ $(c)$ $H_3C-OH, H_3C-SH$

$(a)$ Discuss the significance/applications of dipole moment.
$(b)$ Represent diagrammatically the bond moments and the resultant dipole moment in $CO_2, NF_3$ and $CHCl_3$.

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Assertion : Molecules of larger size have higher polarizability.
Reason : Polarizability is observed only in those molecules which have a permanent dipole moment.

Which out of $NH_{3}$ and $NF_{3}$ has a higher dipole moment and why?

Which of the following compounds has a permanent dipole moment?

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